4k^2-10k-36=0

Solution for 4k^2-10k-36=0 equation:

4k^2-10k-36=0

a = 4; b = -10; c = -36;
Δ = b2-4ac
Δ = -102-4·4·(-36)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-26}{2*4}=\frac{-16}{8}
=-2
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+26}{2*4}=\frac{36}{8}
=4+1/2
$